isywiz
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#1
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Can you help me answer this question?

Given that (x-p)(2x^2+11x+15) = (x^2-9)(2x+q), for all values of x, find the values of the constants p and q.

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B_9710
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You should recogonise that x^2-9 is the difference of 2 squares and can be written as (x-3)(x+3)
This would suggest that p=3 and that 2x^2+11x+15 can be split into 2 brackets - with one of the brackets being (x+3)
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isywiz
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(Original post by B_9710)
You should recogonise that x^2-9 is the difference of 2 squares and can be written as (x-3)(x+3)
This would suggest that p=3 and that 2x^2+11x+15 can be split into 2 brackets - with one of the brackets being (x+3)
So would Q = 5???
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B_9710
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Yes it would be.
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isywiz
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(Original post by B_9710)
Yes it would be.
Thank you
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