# As Maths helpWatch

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Thread starter 4 years ago
#1
Can you help me answer this question?

Given that (x-p)(2x^2+11x+15) = (x^2-9)(2x+q), for all values of x, find the values of the constants p and q.

Thanks
0
4 years ago
#2
You should recogonise that x^2-9 is the difference of 2 squares and can be written as (x-3)(x+3)
This would suggest that p=3 and that 2x^2+11x+15 can be split into 2 brackets - with one of the brackets being (x+3)
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Thread starter 4 years ago
#3
(Original post by B_9710)
You should recogonise that x^2-9 is the difference of 2 squares and can be written as (x-3)(x+3)
This would suggest that p=3 and that 2x^2+11x+15 can be split into 2 brackets - with one of the brackets being (x+3)
So would Q = 5???
0
4 years ago
#4
Yes it would be.
0
Thread starter 4 years ago
#5
(Original post by B_9710)
Yes it would be.
Thank you
0
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