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# Algebra of Complex Numbers Help watch

1. I'm having difficulty solving a maths question, I don't even know how to start to be honest. It's:

Given the equation z + 2iz =8 + 7i express z in the form a + ib

please note that z is the complex conjugate of z, I just wasn't sure how I should type it on here
2. (Original post by anoymous1234)
I'm having difficulty solving a maths question, I don't even know how to start to be honest. It's:

Given the equation z + 2iz =8 + 7i express z in the form a + ib

please note that z is the complex conjugate of z, I just wasn't sure how I should type it on here
Let z = a + bi, giving z* = a - bi (the conjugate can be written z*). If you substitute these into the equation, collect like terms and compare coefficients, you should get to the answer.
3. (Original post by anoymous1234)
I'm having difficulty solving a maths question, I don't even know how to start to be honest. It's:

Given the equation z + 2iz =8 + 7i express z in the form a + ib

please note that z is the complex conjugate of z, I just wasn't sure how I should type it on here
I'd try substituting z = a + ib and the complex conj as a - ib then what could you do?
4. (Original post by SH0405)
Let z = a + bi, giving z* = a - bi (the conjugate can be written z*). If you substitute these into the equation, collect like terms and compare coefficients, you should get to the answer.
but if i sub in a+ib and a-ib i can't express z in the form a+ib as I no longer have a z
5. (Original post by anoymous1234)
but if i sub in a+ib and a-ib i can't express z in the form a+ib as I no longer have a z
That's the whole point. You need the values of a and b in order to be able to express z in that form.

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