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Logarithms math problem :(

I've been trying to simplify this, but I can't. Could somebody give me through the first steps?
log(2root10) - 1/3 log (0.8) - log (10/3)
I got to: -1/2 + log 6 - 1/3 log (0.8) but I'm stuck there.
The solution should be -1/6 + log 3
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Original post by Ferdiee
I've been trying to simplify this, but I can't. Could somebody give me through the first steps?
log(2root10) - 1/3 log (0.8) - log (10/3)
I got to: -1/2 + log 6 - 1/3 log (0.8) but I'm stuck there.
The solution should be -1/6 + log 3

Observe that:
13log(0.8)=13log(810)-\frac{1}{3}\log(0.8)=-\frac{1}{3}\log(\frac{8}{10})
Recall that: log(x)log(y)=log(xy) and  log(xn)=nlog(x)\log(x)-\log(y)=\log(\frac{x}{y}) \text{\ and \ } \log(x^n)=n\log(x)
The rest should then sort itself out.

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