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A discrepency in p6 question? watch

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    Okay; look at Q2 on this here paper:

    http://www.aqa.org.uk/qual/gceasa/qp...W-QP-Jan02.pdf

    And work it out, first using the vectors A to B and B to C

    You should get d = 6 and n= vector (1 2 3)

    this is correct.

    Now try with A to B and A to C

    I don't know if I've got it wrong, with the signs int he cross product bit, but does this not give n = (-1 -2 3) and d =0???
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    (Original post by Mat666)
    Okay; look at Q2 on this here paper:

    http://www.aqa.org.uk/qual/gceasa/qp...W-QP-Jan02.pdf

    And work it out, first using the vectors A to B and B to C

    You should get d = 6 and n= vector (1 2 3)

    this is correct.

    Now try with A to B and A to C

    I don't know if I've got it wrong, with the signs int he cross product bit, but does this not give n = (-1 -2 3) and d =0???
    Youve done it wrong ABxAC = i + 2j + 3k
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    AB = (-3 3 -1) AC = (-2 1 0)

    A x B = (1 2 3)
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    cheers, just checking...
 
 
 
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Updated: June 10, 2004

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