The Student Room Group
Reply 1
P(A/B') = P(AnB')/P(B') = 4/5
since P(B') = 1/2, P(AnB') = 2/5

This can now be put onto a venn diagram - events are mutually exclusive because you were told P(A) = 2/5 so none of A intersects with B
Reply 2
Bebop
Can someone show me how to put this info on a vien diagram

The events A and B are such that P(A) = 2/5, P(B) = 1/2 and P(A|B') = 4/5.

a) Find

i) P(A n B)

ii)P (a u b)

iii) P(a u b)

iv) P(a|b)

Thanks


i) Mutually exclusive by proving that P(AnB') = P(A) therefore = 0
ii) 2/5 + 4/5 = 9/10
iv) (since iii) is the same) because P(AnB) = 0 answer = 0

Reply 3
so if they are mutually exclusive and there is no AnB what do you put in that middle bit of the venn diagram? do you put zero or do you keep the circles seperate?
Reply 4
keep them separate