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Log inequality, help please!

Hey, I'm stuck on this question:
Find the smallest integer satisfying the inequality 2n>100643
I tried the following:
nlog2>643log100
n>(643log100)/(log2) which comes out as 4271 which is pretty ridiculous considering.
could anyone give me a helping hand here? :smile: thanks!
4272 is the right answer yeah.
You get n>4271.99
so the smallest integer it can be is 4272.

You were right basically.
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Exephy
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Original post by whydoidothis?
4272 is the right answer yeah.
You get n>4271.99
so the smallest integer it can be is 4272.

You were right basically.


Oh, my bad. I plugged it back in (2^4273-100^643) and got some huge number like 10^1300, I just guessed it would be smaller if I was right. Anyway, thanks

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