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What am I doing wrong? (Coordinating geometry in x,y plane)

"Find an equation of the line that passes through (5,5) and is perpendicular to line y=(2/3)x + 5. Write in ax+by+c=0 form"

I attempted this and only got one bloody sign wrong so I was hoping you could help me see where I slipped up?

y=(2/3)x+5
m=2/3
Perpendicular of m = -(3/2)

Now I will use the y-y1=m(x-x1) rule.

y-5=-(3/2) (x-5)
y-5=-(3/2)x + (15/2)
and from here I should supposedly get y-5=-(3/2)x + (5/2)

However I don't see how.
-3/2 multiplied by -5 equals POSITIVE 15/2.
Then you ADD 5 to both sides (which is equal to 10/2) meaning I should get 25/2.

What am I doing wrong?

ps. The final answer is 3x+2y-5=0
Reply 1
Avatar for B_9710
B_9710
18
You're right. The equation is 3x+2y=25
The answer which you are apparently supposed to get is wrong
The answer should be 3x+2y-25=0

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