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# integration. watch

1. nothing to see here
2. What's the equation of the curve ?
3. Oh yeah 11 III, I hear you.
4. (Original post by ihatehannah)
for 11 III

you do the area under the line take away the area under the curve, i got the area under the curve to be 5.8333 but i keep getting wrong values for the area under the line, i've integrated y= 0.5x + 3 with respect to x which gave me 0.25x^2, plugged in the values and took away, but keep getting 1.25.
5. (Original post by ihatehannah)
for 11 III

you do the area under the line take away the area under the curve, i got the area under the curve to be 5.8333 but i keep getting wrong values for the area under the line, i've integrated y= 0.5x + 3 with respect to x which gave me 0.25x^2, plugged in the values and took away, but keep getting 1.25.

http://www.ocr.org.uk/Images/130160-...nced-level.pdf
You haven't integrated the 3 as well as the 0.5x. Also I'm not sure integration is the best way to find the area under a straight line, using area of trapezium has gotta be easy and less chance for errors.
6. (Original post by Zacken)
omg i integrated the first term and differniated the second for some reason
7. (Original post by ihatehannah)
nothing to see here
Again... I've already talked to you about this. If you had a question, no matter how silly the mistake, if you've had it answered, have the courtesy to thank the person and not delete the thread, somebody else might find it useful. I find what you're doing very rude and you're putting people off wanting to help you.

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