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# How to expand y-1/7 = 2/7(x- -3/4) watch

1. The fractions are throwing me off. The book says the answer is y = 2/7x +5/14
It needs to be in y=mx+c form.
2. y - 1/7 = 2/7(x - -3/4)
y - 1/7 = 2/7(x + 3/4)
y - 1/7 = 2x/7 + 6/28
y = 2x/7 + 5/14
3. x everything by 7 to get 7y -1 = 2(x- -3/4)

therefore: 7y -1 = 2x + 3/2

therefore 7y = 2x + 5/2

therefore y = 2/7x + 5/14

hope that helps, slightly longer way but gets rid of the fractions early on.
4. (Original post by Ben Hunt)
x everything by 7 to get 7y -1 = 2(x- -3/4)

therefore: 7y -1 = 2x + 3/2

therefore 7y = 2x + 5/2

therefore y = 2/7x + 5/14

hope that helps, slightly longer way but gets rid of the fractions early on.
I think I understand.

As for cancelling, the right hand side is one group/term, so 2/7(x--3/4) is the same as [2(x- - 3/4)]\7. If the divide by 7 is inverted to cancel it, that has to happen to all terms on left hand side, which makes 7y -1 from y - 1/7. I hope that's right.

Thanks to both.

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Updated: October 18, 2015
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