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    I have done the question, im just not sure about it, here it is.

    The functions f and g are defined with their respective domains by:
    f(x)=x-1 for all real values of x
    g(x)=6/x+3 for all real values of x, x cannot equal -3

    the composite function fg is defined by h

    a) Find h(x) i got (6/x+3)-2

    b)i) Find h^-1(x), where h^-1 is the inverse of h and then find the range.

    This is the question im not sure about, i got the answer h^-1(x)= -3x/x+2
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    (Original post by harrybo6)
    I have done the question, im just not sure about it, here it is.

    The functions f and g are defined with their respective domains by:
    f(x)=x-1 for all real values of x
    g(x)=6/x+3 for all real values of x, x cannot equal -3

    the composite function fg is defined by h

    a) Find h(x) i got (6/x+3)-2

    b)i) Find h^-1(x), where h^-1 is the inverse of h and then find the range.

    This is the question im not sure about, i got the answer h^-1(x)= -3x/x+2
    h(x) = 6/x + 1

    y = 6/x + 1

    x = 6/y + 1

    etc
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    (Original post by the bear)
    h(x) = 6/x + 1

    y = 6/x + 1

    x = 6/y + 1

    etc
    how did you get h(x)=6/x +1?
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    you may need to put more brackets in to your expression for g(x):

    either fg(x) = 6/x + 3 -1

    or fg(x) = 6/( x + 3 ) -1

    :holmes:
 
 
 
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