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    8 root 2 * 3 root 3
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    Look at my private message where i explained this earlier
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    (Original post by heyitscraziix)
    8 root 2 * 3 root 3
    A root(B) * C root(D)
    =A*root(B) * C*root(D)
    =(A*C)*root(B*D)

    so 8 root 2 * 3 root 3
    =24 root(6)

    sorry no latex
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    (Original post by genius10)
    A root(B) * C root(D)
    =A*root(B) * C*root(D)
    =(A*C)*root(B*D)

    so 8 root 2 * 3 root 3...
    =24 root(6)


    This confused me. The a and bs
    sorry no latex

    This conused me th bs and as
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    (Original post by heyitscraziix)
    This conused me th bs and as
    What do you find confusing about it? Just multiply the numbers before the surds together, and then multiply the roots together. Then simplify if you need to.
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    (Original post by genius10)
    What do you find confusing about it? Just multiply the numbers before the surds together, and then multiply the roots together. Then simplify if you need to.
    I mean im tryinng to work
    7 root 6 times 3 root 2
    And i multiplied 7*3
    And 6 root and 2 root
    And the answers wrong somehow
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    (Original post by heyitscraziix)
    I mean im tryinng to work
    7 root 6 times 3 root 2
    And i multiplied 7*3
    And 6 root and 2 root
    And the answers wrong somehow
    root 6 * root 2 = root 12
    root 12 = root 4 * root 3
    root 4 = 2
    =2root3

    now just multiply by 21
 
 
 
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