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    f(x) =  e^x

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    f(|x|) can be equally written as a quadratic equation in the form  1+ax^2+bx where a & b are to be determined.
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    (Original post by AK 12)
    f(x) =  e^x

    Show that

    f(|x|) can be equally written as a quadratic equation in the form  1+ax^2+bx where a & b are to be determined.
    what was that again?
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    (Original post by AK 12)
    f(x) =  e^x

    Show that

    f(|x|) can be equally written as a quadratic equation in the form  1+ax^2+bx where a & b are to be determined.
    Are you saying that \displaystyle e^{|x|} = 1 = bx + ax^2 for some constant a,b \in \mathbb{R}? :rofl:
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    (Original post by AK 12)
    f(x) =  e^x

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    f(|x|) can be equally written as a quadratic equation in the form  1+ax^2+bx where a & b are to be determined.
    \displaystyle \exp(|x|) = \sum_{k=0}^{\infty} \frac{|x|^k}{k!}, so...
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    (Original post by AK 12)
    f(x) =  e^x

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    f(|x|) can be equally written as a quadratic equation in the form  1+ax^2+bx where a & b are to be determined.
    \displaystyle a=\frac{-1}{x^2}

    \displaystyle b=\frac{e^{|x|}}{x}

    Or not. Please post the question exactly as you see it.
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    (Original post by notnek)
    \displaystyle a=\frac{-1}{x^2}

    \displaystyle b=\frac{e^{|x|}}{x}

    Or not. Please post the question exactly as you see it.
    I don't think that is correct, a quadratic equation is a polynomial of the form ax^2 + bx + c with a, b, c constant and a \neq 0.
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    (Original post by Zacken)
    I don't think that is correct, a quadratic equation is a polynomial of the form ax^2 + bx + c with a, b, c constant and a \neq 0.
    A quadratic equation also contains an '='.

    I think we can make up our own rules for this question
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    (Original post by notnek)
    A quadratic equation also contains an '='.

    I think we can make up our own rules for this question
    Fair enough, although he probably meant quadratic function. I think we can both agree that this post is a trainwreck...
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    (Original post by notnek)
    \displaystyle a=\frac{-1}{x^2}

    \displaystyle b=\frac{e^{|x|}}{x}

    Or not. Please post the question exactly as you see it.
    (Original post by Zacken)
    \displaystyle \exp(|x|) = \sum_{k=0}^{\infty} \frac{|x|^k}{k!}, so...
    (Original post by TeeEm)
    what was that again?
    (Original post by Zacken)
    Are you saying that \displaystyle e^{|x|} = 1 = bx + ax^2 for some constant a,b \in \mathbb{R}? :rofl:
    It was a step question. I'm preparing for it and need help
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    (Original post by AK 12)
    It was a step question. I'm preparing for it and need help
    Post a photo of the actual question please
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    (Original post by AK 12)
    It was a step question. I'm preparing for it and need help
    Which paper/question?
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    (Original post by AK 12)
    It was a step question. I'm preparing for it and need help
    Can we please see the full question, or at the very least tell us which paper and question it is?
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    (Original post by 16Characters....)
    Can we please see the full question, or at the very least tell us which paper and question it is?
    (Original post by notnek)
    Which paper/question?
    (Original post by TeeEm)
    Post a photo of the actual question please
    It also says a & b can be transcendental
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    (Original post by AK 12)
    It also says a & b can be transcendental
    0/10 troll.
 
 
 
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