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    x^1/2 =4

    And

    2x^3/2 = 6x
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    (Original post by FluffyCherry)
    x^1/2= 4
     2x^3/2= 6x
    For each one you need to treat both sides of the equations such that you make x be on its own, without any coefficients, power ect.

    For the first one, you know that if you square both sides you will have x=16.
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    X^1/2 = root x
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    (Original post by Mehrdad jafari)
    For each one you need to treat both sides of the equations such that you make x be on its own, without any coefficients, power ect.

    For the first one, you know that if you square both sides you will have x=16.
    I see, thanx
    and how about 2x^3/2 = 6x
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    (Original post by FluffyCherry)
    I see, thanx
    and how about 2x^3/2 = 6x
    What do you think first you would have to do with both sides to eliminate the coefficient of x?
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    (Original post by Mehrdad jafari)
    x
    If you want to Latex a superscript with more than one character then enclose it in {}, for example, x^{1/2} produces x^{1/2} whilst x^1/2 produces x^1/2
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    (Original post by FluffyCherry)
    I see, thanx
    and how about 2x^3/2 = 6x
    Factorise and solve.
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    (Original post by Mehrdad jafari)
    What do you think first you would have to do with both sides to eliminate the coefficient of x?
    2x^3/2 = 6x
    2x^3/2 - 6x=0
    2x(x^1/2 -3)=0

    So 2x =0 Or x^1/2 -3 =0 x^1/2 =3 And now that's the part was I was confused, do I square the
    answer or square root it?
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    (Original post by FluffyCherry)
    2x^3/2 = 6x
    2x^3/2 - 6x=0
    2x(x^1/2 -3)=0

    So 2x =0 Or x^1/2 -3 =0 x^1/2 =3 And now that's the part was I was confused, do I square the
    answer or square root it?
    Your factorized equation is the same type of problem as part (a)...

    Also, it is helpful to realise that x^{\frac{1}{2}}=\sqrt{x}.
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    (Original post by Zacken)
    If you want to Latex a superscript with more than one character then enclose it in {}, for example, x^{1/2} produces x^{1/2} whilst x^1/2 produces x^1/2
    Thanks for the advice! i usually don't use latex

    (Original post by FluffyCherry)
    2x^3/2 = 6x
    2x^3/2 - 6x=0
    2x(x^1/2 -3)=0

    So 2x =0 Or x^1/2 -3 =0 x^1/2 =3 And now that's the part was I was confused, do I square the
    answer or square root it?
    As others have pointed out, you should realise that x1/2=root3 which was the case in the first part
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    you do not need latex...





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    (Original post by the bear)
    you do not need latex...





    Where do you get that? I couldn't find it
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    (Original post by Mehrdad jafari)
    Where do you get that? I couldn't find it
    just search "ascii square root" on a search engine. google is a good one ?
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    (Original post by the bear)
    just search "ascii square root" on a search engine. google is a good one ?
    Oh right! So it's kind of an image?
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    (Original post by Mehrdad jafari)
    Oh right! So it's kind of an image?
    i... i guess ?
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    You square both sides so x=9
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    (Original post by the bear)
    you do not need latex...





    Using \LaTeX takes less time to write up than searching for asciii square root in a search engine (for me), not to mention that it is vastly neater.
 
 
 
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