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    So if you were hydrolising an ester and adding NaOH to work out the rate of reaction or whatever, and you plotted log(V final - V titre) against time and got a straight line, then repeated the experiment with a higher temp, how would the graph change?
    Hope that makes sense,
    Thanks
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    https://www.youtube.com/watch?v=WEODL3VqlZw would that help?
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    (Original post by white_o)
    So if you were hydrolising an ester and adding NaOH to work out the rate of reaction or whatever, and you plotted log(V final - V titre) against time and got a straight line, then repeated the experiment with a higher temp, how would the graph change?
    Hope that makes sense,
    Thanks
    If you increase the temperature, you will increase the rate of hydrolysis. Thus a the larger volume of carboxylic acid will be produced in the same time period. As a result you will need more NaOH to neutralise the additional carboxylic acid, so will have a larger 'V titre'.

    I think the value for 'V final' will not alter despite the higher temperature. Overall the value for 'log(V final - V titre)' will be smaller, so the gradient of the graph will be smaller.

    Hope this helped
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    (Original post by white_o)
    So if you were hydrolising an ester and adding NaOH to work out the rate of reaction or whatever, and you plotted log(V final - V titre) against time and got a straight line, then repeated the experiment with a higher temp, how would the graph change?
    Hope that makes sense,
    Thanks
    Why would you reflux when doing an experiment of ester hydrolysis
 
 
 
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