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    pls view attached picture -- shouldn't it be the other way round?? noncompetitive vs no inhibitor at all. shouldn't the noncompetitive have a lower gradient than no inhibitor? is the labelling of the graph wrong or am i missing something?
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    I think you're right because the rate of reaction would be lowered in the presence of a non competitive inhibitors
 
 
 
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Updated: October 20, 2015
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