pls view attached picture -- shouldn't it be the other way round?? noncompetitive vs no inhibitor at all. shouldn't the noncompetitive have a lower gradient than no inhibitor? is the labelling of the graph wrong or am i missing something?
x Turn on thread page Beta
competitive/noncompetitive inhibition questiON watch
- Thread Starter
- 20-10-2015 12:46
- 20-10-2015 22:40
I think you're right because the rate of reaction would be lowered in the presence of a non competitive inhibitors