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# FP2 Polar equations watch

1. Find the Cartesian equation of the curve with polar equation r=cos^2Θ. Hence show that the equation of the tangent to the curve at the point ((1/2), ((1/4)pi)) is
r=1/(sqrt2(3sinΘ-cosΘ))

Ive done the first part and found the correct Cartesian equation:
(x^2+y^2)^3 =x^4 but am unsure where to go from here
2. (Original post by Mathematicus65)
Find the Cartesian equation of the curve with polar equation r=cos^2Θ. Hence show that the equation of the tangent to the curve at the point ((1/2), ((1/4)pi)) is
r=1/(sqrt2(3sinΘ-cosΘ))

Ive done the first part and found the correct Cartesian equation:
(x^2+y^2)^3 =x^4 but am unsure where to go from here
Since it says "hence show", I'd work out the equation of the tangent in cartesian, and then convert.
3. (Original post by ghostwalker)
Since it says "hence show", I'd work out the equation of the tangent in cartesian, and then convert.
Thank you, i have done it now anyway, forgot that they had given me the polr coordinates, because I couldn't find the Cartesian coordinates to find the gradient but obviously just had to convert between the two

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