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    How to do
    1/4 ln(4) - 1/3 ln(2)
    to get an answer in ln form?
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    Can explain what it is you want a little more clearly?
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    (Original post by Thediplomat56)
    Can explain what it is you want a little more clearly?
    Solve 1/4 ln(4) - 1/3 ln(2) giving your answer in ln.
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    (Original post by Thediplomat56)
    This?Attachment 470535
    No, this is C3 maths natural logarithms with a fraction before the ln
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    (Original post by Sayless)
    How to do
    1/4 ln(4) - 1/3 ln(2)
    to get an answer in ln form?
    Consider using this log law:

    a log b = log (b^a).

    ln is just the same as log to the base e, it's just a simpler way of writing it, you should treat it just like any other log when using log laws.
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    (Original post by Sayless)
    No, this is C3 maths natural logarithms with a fraction before the ln
    Wrong photo my badName:  image3.jpg
Views: 65
Size:  488.2 KB
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    (Original post by Thediplomat56)
    Wrong photo my badName:  image3.jpg
Views: 65
Size:  488.2 KB
    Np, thanks a lot
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    Think about Ln being Log base e.
    what do the laws of logs say that xlogy is always equal to?
    What can you do to combine two logs with the same base into 1?
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    http://www.cymath.com/answer.php?q=(...-%20(1%2F3)ln2

    This website is a good way to see step-by-step how to solve your equation
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    (Original post by Sayless)
    Np, thanks a lot
    That is the same answer that I got! I am not sure if it's simplified enough though >.> Have you got the answers?
 
 
 
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