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# AS Maths polynomials/factor theorem question watch

1. Hi,
Would anybody be able to help me answer this question:

I got 1 for B using simultaneous equations (after the factor theorem for both) but then wasn't sure how to get a and c?

The answers are a= 2, b=1, c=2
2. (Just question 6)
3. (Original post by orangeee22)
(Just question 6)
You sub your value of b back into both equations which should give you another pair of equations to solve simultaneously
4. (Original post by orangeee22)
Hi,
Would anybody be able to help me answer this question:

I got 1 for B using simultaneous equations (after the factor theorem for both) but then wasn't sure how to get a and c?

The answers are a= 2, b=1, c=2
If you divide by x, then it also means you're dividing by (x-0).
The remainder is 2. This means f(0) = 2

That eliminates everything except c.
So now you know what c is. You calculated b.

All that's left is a.

That's easy.
5. (Original post by 99-bdk23)
You sub your value of b back into both equations which should give you another pair of equations to solve simultaneously

But if I substitute the value for b back into the equations I just get two of the same equation: a+c=4 so you can't solve it simultaneously?
6. (Original post by RMNDK)
If you divide by x, then it also means you're dividing by (x-0).
The remainder is 2. This means f(0) = 2

That eliminates everything except c.
So now you know what c is. You calculated b.

All that's left is a.

That's easy.
Ohh thank you! I didn't read the question properly and didn't see dividing by x (I thought the second '2' was a typo- there's a lot in this textbook)

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