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    Hi,
    Would anybody be able to help me answer this question:
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    I got 1 for B using simultaneous equations (after the factor theorem for both) but then wasn't sure how to get a and c?

    The answers are a= 2, b=1, c=2
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    (Just question 6)
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    (Original post by orangeee22)
    (Just question 6)
    You sub your value of b back into both equations which should give you another pair of equations to solve simultaneously
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    (Original post by orangeee22)
    Hi,
    Would anybody be able to help me answer this question:
    Name:  20151020_195105.jpg
Views: 104
Size:  500.3 KB

    I got 1 for B using simultaneous equations (after the factor theorem for both) but then wasn't sure how to get a and c?

    The answers are a= 2, b=1, c=2
    If you divide by x, then it also means you're dividing by (x-0).
    The remainder is 2. This means f(0) = 2

    That eliminates everything except c.
    So now you know what c is. You calculated b.

    All that's left is a.

    That's easy.
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    (Original post by 99-bdk23)
    You sub your value of b back into both equations which should give you another pair of equations to solve simultaneously
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    But if I substitute the value for b back into the equations I just get two of the same equation: a+c=4 so you can't solve it simultaneously?
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    (Original post by RMNDK)
    If you divide by x, then it also means you're dividing by (x-0).
    The remainder is 2. This means f(0) = 2

    That eliminates everything except c.
    So now you know what c is. You calculated b.

    All that's left is a.

    That's easy.
    Ohh thank you! I didn't read the question properly and didn't see dividing by x (I thought the second '2' was a typo- there's a lot in this textbook)
 
 
 
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