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    Hello guys, i need help in knowing what rule to you use for this particular question

    y=x^2ln(x-2)6

    I used the product rule and got:

    U=x^2
    V=ln(x-2)^6

    My question is, when differentiating V, do i use the natural log rule making it
    1/(x-2)^6 or do i use the chain rule? If im talking total rubbish, please provide the solutions. Thanks a lot guys!
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    You use the rule \ln a^b=b \ln a
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    (Original post by Dose of fury)
    Hello guys, i need help in knowing what rule to you use for this particular question

    y=x^2ln(x-2)6

    I used the product rule and got:

    U=x^2
    V=ln(x-2)^6

    My question is, when differentiating V, do i use the natural log rule making it
    1/(x-2)^6 or do i use the chain rule? If im talking total rubbish, please provide the solutions. Thanks a lot guys!
    You could use the chain rule, or see above.
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    (Original post by nerak99)
    You use the rule \ln a^b=b \ln a
    thanks.
 
 
 
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