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# Can anybody do this maths question as i am struggling with it? watch

1. Express 2/ 3-√3 in the form a+b√3, where a and b are rational numbers to be found
2. (Original post by Mathsgu)
Express 2/ 3-√3 in the form a+b√3, where a and b are rational numbers to be found
rationalise the denominator by multiplying both the top and bottom by 3+√3
3. (Original post by Mathsgu)
Express 2/ 3-√3 in the form a+b√3, where a and b are rational numbers to be found
Try rationalising the denominator, i.e. times the numerator and the denominator by 3+√3

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4. (Original post by Ben4)
Try rationalising the denominator, i.e. times the numerator and the denominator by 3+√3

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Thank you, what would be the next steps in working this out? I rationalized this last time but did not get the right answer
5. (Original post by Mathsgu)
Thank you, what would be the next steps in working this out? I rationalized this last time but did not get the right answer
Can I see your workings? Maybe you didnt simplify it correctly.

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6. (Original post by Mathsgu)
Thank you, what would be the next steps in working this out? I rationalized this last time but did not get the right answer
We can't post the answer but will look at your working to help you.
7. times that numerator by 3+√3 but the denominator by 3-√3
8. (Original post by Suprite)
times that numerator by 3+√3 but the denominator by 3-√3
no - you must multiply numerator and denominator by the same or you won't have an equivalent fraction!
9. (Original post by Suprite)
times that numerator by 3+√3 but the denominator by 3-√3
This is just wrong .
10. [QUOTE=Ben4;60086169]Can I see your workings? Maybe you didnt simplify it correctly.

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Yeah sure I worked it out like this. I tried rationalizing it to begin with by times the top and bottom by 3+squareroot 3 and I ended up with 6+ 2squareroot 3 over 6. I'm most likely multiplying it in the wrong way but I don't know where i'm going wrong.
11. (Original post by Mathsgu)
Yeah sure I worked it out like this. I tried rationalizing it to begin with by times the top and bottom by 3+squareroot 3 and I ended up with 6+ 2squareroot 3 over 6. I'm most likely multiplying it in the wrong way but I don't know where i'm going wrong.
This is correct. Simplify it down and you get 1+(1/3)rt3
12. [QUOTE=Mathsgu;60126653]
(Original post by Ben4)
Can I see your workings? Maybe you didnt simplify it correctly.

Posted from TSR Mobile[/QUOTE
Yeah sure I worked it out like this. I tried rationalizing it to begin with by times the top and bottom by 3+squareroot 3 and I ended up with 6+ 2squareroot 3 over 6. I'm most likely multiplying it in the wrong way but I don't know where i'm going wrong.
13. (Original post by C0pper)
Assuming you mean rt3 there instead of rt5, this is correct. Simplify it down and you get 1+(1/3)rt3
Yeah sorry that was a typo I meant squareroot 3. Thank you for the help, I think I was making a silly mistake when simplifying it.

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