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    A particle B of mass 0.3kg is moving with velocity (7i+4j)m/s when it collides with a stationary particle C of mass 0.5kg. immediately after the collision C moves with velocity (6i+0) m/s.

    a) find the velocity of B immediately after the collision.
    b) find the speed of B immediately after the collision
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    how far did you get harry ?
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    (Original post by harrybo6)
    A particle B of mass 0.3kg is moving with velocity (7i+4j)m/s when it collides with a stationary particle C of mass 0.5kg. immediately after the collision C moves with velocity (6i+0) m/s.

    a) find the velocity of A immediately after the collision.
    b) find the speed of A immediately after the collision
    You must've learned the equation m1u1 + m2u2 = m1v1 + m2v2 right?
    m1 is the mass of particle B
    m2 is the mass of particle C
    Can you tell me what v1,v2,u1 and u2 are? If so just plug them into the equation.
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    You didnt mention a particle A but if you got your letters wrong you can just use conservation of momentum.
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    (Original post by ComputerMaths97)
    You must've learned the equation m1v1 + m1u1 = m2v2 + m2u2 right?
    m1 is the mass of particle B
    m2 is the mass of particle C
    Can you tell me what v1,v2,u1 and u2 are? If so just plug them into the equation.
    i can tell you what i did but im not sure if im right! i did 0.3x(7i+4j) which i got
    2.1i+1.2j = before momentum
    after momentum =2.1i+1.2j = 0.3v + 0.5(6i) = 0.3v+3i
    so i rearranged moving 3i over -0.9i+1.2j = 0.3v devided by 0.3
    =-3i+4j
    thats what i got for part a) but part b i have no clue i thought they were the same, so i just squared 3 and 4 then took the sqare number of that which got me 5
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    (Original post by CheetahCurtis)
    You didnt mention a particle A but if you got your letters wrong you can just use conservation of momentum.
    sorry didnt see that, thanks for letting me know
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    (Original post by harrybo6)
    i can tell you what i did but im not sure if im right! i did 0.3x(7i+4j) which i got
    2.1i+1.2j = before momentum
    after momentum =2.1i+1.2j = 0.3v + 0.5(6i) = 0.3v+3i
    so i rearranged moving 3i over -0.9i+1.2j = 0.3v devided by 0.3
    =-3i+4j
    thats what i got for part a) but part b i have no clue i thought they were the same, so i just squared 3 and 4 then took the sqare number of that which got me 5
    Perfect!
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    (Original post by ComputerMaths97)
    Perfect!
    Thank you
 
 
 
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