Hey there! Sign in to join this conversationNew here? Join for free
x Turn on thread page Beta
    • Thread Starter
    Offline

    16
    ReputationRep:
    Name:  image.jpeg
Views: 143
Size:  410.0 KB
    Can someone help me as to where to start? I think it may be simultaneous☹️
    Offline

    2
    ReputationRep:
    f(1)=f(-1/2) i think


    Posted from TSR Mobile
    • Very Important Poster
    Online

    21
    ReputationRep:
    Very Important Poster
    (Original post by JaisulNaikJN)
    f(1)=f(-1/2) i think


    Posted from TSR Mobile
    I'm not sure if that's necessarily true.

    (Original post by ozmo19)
    Name:  image.jpeg
Views: 143
Size:  410.0 KB
    Can someone help me as to where to start? I think it may be simultaneous☹️
    I would suggest long division but there may be a quicker method.
    Offline

    18
    ReputationRep:
    Would yuo not do polynomial division...? Thats what I would do
    • Study Helper
    Offline

    15
    Study Helper
    (Original post by ozmo19)
    Name:  image.jpeg
Views: 143
Size:  410.0 KB
    Can someone help me as to where to start? I think it may be simultaneous☹️
    As JaisulNaikJN said, "f(1)=f(-1/2)"

    q will cancel and you're left with an equation solely in p.
    Offline

    0
    ReputationRep:
    I think p=18?
    Offline

    20
    ReputationRep:
    Okay the steps to do this:

    1) Do a long polynomial division #1:
    f(x) / (x-1) --> You'll get a remainder, we shall call #1

    2) Do a second polynomial division #1
    f(x) / (2x +1) --> You'll get a remainder, we shall call #2

    3) Set remainder #1 = remainder #2. From this, you should be able to work out what p is. You might need to re-arrange the remainders in the form q= p(x).

    Video help for steps 1 and 2:
    https://www.khanacademy.org/math/alg...omial-division

    Website help for steps 1 and 2:
    http://www.purplemath.com/modules/polydiv2.htm

    As to why polynomial division is important to real world applications, well it may help us simplify equations down, potentially so that we can find solutions more easily. Maybe a mathematician can expand more on some reasons!
    Offline

    2
    ReputationRep:
    (Original post by SeanFM)
    I'm not sure if that's necessarily true.



    I would suggest long division but there may be a quicker method.
    That is true because the Remainder Theorem states that f(x) divided by (x-p) gives the remainder f(p). You can do the same with both of those and you get the same remainder, therefore both are equal. you can then use simultaneous equations to work out your answer
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: October 30, 2015
Poll
Do you like carrot cake?
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.