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# Logs watch

1. Write these as a single logarithm:-

c)

The book has provided the solution of

But I'm uncertain as to whether my solution is also valid:-

Many thanks.
2. (Original post by supreme)
Write these as a single logarithm:-

c)

The book has provided the solution of

But I'm uncertain as to whether my solution is also valid:-

Many thanks.
It's correct; but it's not a single logarithm. So false.
3. A single logarithm means just one term, with Log in it.

[Let Log = Log to the base a... Because I'm on mobile, it makes it easier]

First, use the power rule.
xLogy = Logy^x

So:
5Loga = Loga^5
(1/3)Log27 = Log27^(1/3) = Log3

You now have:
Loga^5 + Log3 + Log2

Now, use the product rule
Logx + Logy = Logxy

So:
Log(a^5x3x2)

You now have:
Log(6a^5)
4. (Original post by Jamdroid)

[Let Log = Log to the base a... Because I'm on mobile, it makes it easier]

First, use the power rule.
xLogy = Logy^x

So:
5Loga = Loga^5
(1/3)Log27 = Log27^(1/3) = Log3

You now have:
Loga^5 + Log3 + Log2

Now, use the product rule
Logx + Logy = Logxy

So:
Log(a^5x3x2)

You now have:
Log(6a^5)
Thanks
5. (Original post by multiratiunculae)
It's correct; but it's not a single logarithm. So false.
Yes, just shows I didn't read the question properly.

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