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    Hello

    How do I solve this?

    Find the derivative dy/dx of/for the following function:

    axy^b+ln(axy)=(ay+bx)^b+c, where a, b, and c are constants
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    This isis a question on implicit differentiation. To start you off. Axy^b is a product so you use the product rule and y^b differentiates to by^{b-1} \times \frac {dy}{dx} wherevyou have used the chain rule because y is an function of x
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    You are going to have a few dy/dx terms when you differentiate both sides with respect to x- which you will then have to factor out. This is implicit differentiation so just remember that d/dx(y) = dy/dx . d/dy(y) it's almost like the dy's cancel out leaving you with d/dx(y)
    You will also have to use the product rule and know how to differentiate log functions as wel.
 
 
 
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Updated: October 27, 2015
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