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    This is more of economics, but I think it's easy enough

    I have 2 curves:

    1) Q = 180 - 2P ; and
    2) Q = -15 + P

    I got slope as 2 and 1 respectively. Can anybody confirm this please?
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    (Original post by DiceTheSlice)
    This is more of economics, but I think it's easy enough

    I have 2 curves:

    1) Q = 180 - 2P ; and
    2) Q = -15 + P

    I got slope as 2 and 1 respectively. Can anybody confirm this please?
    Shouldn't the first one be -2?

    As slope = \dfrac{\Delta y}{\Delta x} where \Delta represents 'change in'

    As you said, it's more of an economics thing, something I have minimal knowledge about. But if you're looking for the gradient of the line, you would differentiate the equation and set it to = 0 (if you still have any unknown variables)

    \dfrac{dQ}{dP} = -2

    The second one seems fine.
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    (Original post by edothero)
    Shouldn't it be -2?
    As slope = \dfrac{\Delta y}{\Delta x}

    \dfrac{dQ}{dP} = -2

    As you said, it's more of an economics thing, something I have minimal knowledge about, but if you're looking for the gradient of the line, you would differentiate the equation and set it to = 0
    yes... -2 and 1. I'm comparing each other with their absolute values, so I forgot to about the negative sign.

    Alright, thanks for the help :yy:
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    (Original post by DiceTheSlice)
    yes... -2 and 1. I'm comparing each other with their absolute values, so I forgot to about the negative sign.


    Alright, thanks for the help
    Glad I could help!

    Not quite I'm more into Pure Mathematics and Computing
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    (Original post by edothero)
    Glad I could help!

    Not quite I'm more into Pure Mathematics and Computing
    Cool does quantitative analysis come under Pure Mathematics?

    I'm talking about things like standard deviation and Z,T,P values and stuff
 
 
 
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