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# Frictional Forces Problem watch

1. μk=0.200
A 2.0 kg wood block is launched up a wooden ramp that is inclined at a 30 ∘ angle. The block's initial speed is 8.0 m/s . The coefficient of kinetic friction of wood on wood is μk=0.200. What vertical height does the block reach above its starting point?

I'm a bit confused about how to approach this problem. I know that you split the problem into x and y directions, and that Fgy and the normal force cancel out, so you focus on Fgx and the kinetic frictional force.

How do you proceed from there?
2. (Original post by PatchworkTeapot)
μk=0.200
A 2.0 kg wood block is launched up a wooden ramp that is inclined at a 30 ∘ angle. The block's initial speed is 8.0 m/s . The coefficient of kinetic friction of wood on wood is μk=0.200. What vertical height does the block reach above its starting point?

I'm a bit confused about how to approach this problem. I know that you split the problem into x and y directions, and that Fgy and the normal force cancel out, so you focus on Fgx and the kinetic frictional force.

How do you proceed from there?
Have you started by drawing a free body diagram?
3. (Original post by Phichi)
Have you started by drawing a free body diagram?
Yeah, that is how I found the Ff and Fgx will be acting in the same direction (in the x direction) and the forces in the y direction cancel.

FN= mgcos(30)
Ff=0.2FN=0.2mgcos(30)

Fgx=mgsin(30)
If this is correct, how can I continue?
4. (Original post by PatchworkTeapot)
μk=0.200
A 2.0 kg wood block is launched up a wooden ramp that is inclined at a 30 ∘ angle. The block's initial speed is 8.0 m/s . The coefficient of kinetic friction of wood on wood is μk=0.200. What vertical height does the block reach above its starting point?

I'm a bit confused about how to approach this problem. I know that you split the problem into x and y directions, and that Fgy and the normal force cancel out, so you focus on Fgx and the kinetic frictional force.

How do you proceed from there?
Think about the problem and what you're trying to find out: yo're going to push the block up a slope, and find the point at which it stops.

So you can try finding the height at which it's velocity is instantaneously zero (forces approach)

or

You can find the height at which another quantity is zero (easier, this is probably enough of a hint).

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