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    Could someone please explain these maths questions and tell me how to work them out because i am completely lost.
    Thanks
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    i do not know maybe use a protractor (i know its on my maths)
    Maybe do the lesson that goes with it
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    Knowing the diameter for the top of the wrapper, you can work out the circumference at that point. This is the length of arc for the sector....
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    (Original post by Appazap)
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    Could someone please explain these maths questions and tell me how to work them out because i am completely lost.
    Thanks
    Second question: height of cylinder = 6*2.7 = 16.2cm. Volume of cylinder = pi*r^2*h.
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    (Original post by ghostwalker)
    Knowing the diameter for the top of the wrapper, you can work out the circumference at that point. This is the length of arc for the sector....
    i think i need to use θ/360 x d x pi or θ/360 x r2 x pi?

    but i don't know how exactly to get there, im so confused :confused:
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    (Original post by ombtom)
    Second question: height of cylinder = 6*2.7 = 16.2cm. Volume of cylinder = pi*r^2*h.
    oh yeah! that makes perfect sense. I don't even know what i was doing to be honest. Thank you
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    (Original post by Appazap)
    oh yeah! that makes perfect sense. I don't even know what i was doing to be honest. Thank you
    I would rep him if i was u
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    (Original post by Beamer786G-Star)
    I would rep him if i was u
    oops good idea
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    (Original post by Appazap)
    i think i need to use θ/360 x d x pi or θ/360 x r2 x pi?

    but i don't know how exactly to get there, im so confused :confused:
    Look at the cross section. The diameter of the circle at the top of the wrapper is given. What's its circumference?
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    Mymaths is so stupid
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    did u get the answer for the first one??
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    (Original post by ghostwalker)
    Look at the cross section. The diameter of the circle at the top of the wrapper is given. What's its circumference?
    so do you just do 5.6 x pi and that'll give you the circumference?
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    (Original post by EnterNamehereplz)
    Mymaths is so stupid
    trust mee, there isn't even a lesson for this
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    (Original post by User23)
    so do you just do 5.6 x pi and that'll give you the circumference?
    yeah thats what i thought and then you've found the curved bit right?
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    (Original post by User23)
    so do you just do 5.6 x pi and that'll give you the circumference?
    Yes. And that's the length of the arc of the sector.
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    (Original post by Appazap)
    yeah thats what i thought and then you've found the curved bit right?
    So you use that arc length as ghostwalker told us. So it would be 5.6 x pi= 17.5929. then i did 12*pi*x/360= 17.5929 and so i found x to be 168, a nice number
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    (Original post by User23)
    So you use that arc length as ghostwalker told us. So it would be 5.6 x pi= 17.5929. then i did 12*pi*x/360= 17.5929 and so i found x to be 168, a nice number
    oh yeah that makes sense now! Thank you and ghostwalker for helping me with this question, i really appreciate it
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    (Original post by Appazap)
    oh yeah that makes sense now! Thank you and ghostwalker for helping me with this question, i really appreciate it
    You're very welcome xx
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    (Original post by User23)
    So you use that arc length as ghostwalker told us. So it would be 5.6 x pi= 17.5929. then i did 12*pi*x/360= 17.5929 and so i found x to be 168, a nice number
    Why that formula (in bold)?

    If x is in degrees, then converting to radians is x*pi/180
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    (Original post by ghostwalker)
    Why that formula (in bold)?

    If x is in degrees, then converting to radians is x*pi/180
    Radians?
    All I did was just do x/360 x 12 pi = 14.5929....
    Then I made x the subject of the formula
 
 
 
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