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# How do i find angle x watch

1. Attachment 472389472391

Could someone please explain these maths questions and tell me how to work them out because i am completely lost.
Thanks
Attached Images

2. i do not know maybe use a protractor (i know its on my maths)
Maybe do the lesson that goes with it
3. Knowing the diameter for the top of the wrapper, you can work out the circumference at that point. This is the length of arc for the sector....
4. (Original post by Appazap)
Attachment 472389472391

Could someone please explain these maths questions and tell me how to work them out because i am completely lost.
Thanks
Second question: height of cylinder = 6*2.7 = 16.2cm. Volume of cylinder = pi*r^2*h.
5. (Original post by ghostwalker)
Knowing the diameter for the top of the wrapper, you can work out the circumference at that point. This is the length of arc for the sector....
i think i need to use θ/360 x d x pi or θ/360 x r2 x pi?

but i don't know how exactly to get there, im so confused
6. (Original post by ombtom)
Second question: height of cylinder = 6*2.7 = 16.2cm. Volume of cylinder = pi*r^2*h.
oh yeah! that makes perfect sense. I don't even know what i was doing to be honest. Thank you
7. (Original post by Appazap)
oh yeah! that makes perfect sense. I don't even know what i was doing to be honest. Thank you
I would rep him if i was u
8. (Original post by Beamer786G-Star)
I would rep him if i was u
oops good idea
9. (Original post by Appazap)
i think i need to use θ/360 x d x pi or θ/360 x r2 x pi?

but i don't know how exactly to get there, im so confused
Look at the cross section. The diameter of the circle at the top of the wrapper is given. What's its circumference?
10. Mymaths is so stupid
11. did u get the answer for the first one??
12. (Original post by ghostwalker)
Look at the cross section. The diameter of the circle at the top of the wrapper is given. What's its circumference?
so do you just do 5.6 x pi and that'll give you the circumference?
13. (Original post by EnterNamehereplz)
Mymaths is so stupid
trust mee, there isn't even a lesson for this
14. (Original post by User23)
so do you just do 5.6 x pi and that'll give you the circumference?
yeah thats what i thought and then you've found the curved bit right?
15. (Original post by User23)
so do you just do 5.6 x pi and that'll give you the circumference?
Yes. And that's the length of the arc of the sector.
16. (Original post by Appazap)
yeah thats what i thought and then you've found the curved bit right?
So you use that arc length as ghostwalker told us. So it would be 5.6 x pi= 17.5929. then i did 12*pi*x/360= 17.5929 and so i found x to be 168, a nice number
17. (Original post by User23)
So you use that arc length as ghostwalker told us. So it would be 5.6 x pi= 17.5929. then i did 12*pi*x/360= 17.5929 and so i found x to be 168, a nice number
oh yeah that makes sense now! Thank you and ghostwalker for helping me with this question, i really appreciate it
18. (Original post by Appazap)
oh yeah that makes sense now! Thank you and ghostwalker for helping me with this question, i really appreciate it
You're very welcome xx
19. (Original post by User23)
So you use that arc length as ghostwalker told us. So it would be 5.6 x pi= 17.5929. then i did 12*pi*x/360= 17.5929 and so i found x to be 168, a nice number
Why that formula (in bold)?

If x is in degrees, then converting to radians is x*pi/180
20. (Original post by ghostwalker)
Why that formula (in bold)?

If x is in degrees, then converting to radians is x*pi/180
All I did was just do x/360 x 12 pi = 14.5929....
Then I made x the subject of the formula

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