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    Hey,

    My question is:

    When P(x) is divided by (x-1)(x+2) the remainder is 2x+3
    -What is the remainder when it is divided by (x-1)

    I have tried various techniques, and I can't get an answer.

    Thank you!!!
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    When P(x) is divided by (x-1)(x+2) the remainder is 2x+3 means:
    P(x) = (x-1)(x+2)Q(x) + 2x+3
    where Q(x) is some polynomial.

    Find the remainder when 2x+3 is divided by (x-1) and think about how that relates to the remainder when P(x) is divided by (x-1).
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    Alternatively, by the Remainder Theorem, the remainder of P(x) upon division by (x-a) is P(a) for some constant a. Here a is 1.Use that to find the remainder...
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    (Original post by Cycy12)
    Thank you!!!
    As Pronged Lily said.

    And writing your polynomial as:

    P(x)=(x-1)(x+2)Q(x)+(2x+3)

    may assist understanding.
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    (Original post by ghostwalker)
    As Pronged Lily said.

    And writing your polynomial as:

    P(x)=(x-1)(x+2)Q(x)+(2x+3)

    may assist understanding.
    Thank you for your help!

    So, do i just divide 2x+3 by x+1 and look at this remainder?
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    (Original post by Pronged Lily)
    Alternatively, by the Remainder Theorem, the remainder of P(x) upon division by (x-a) is P(a) for some constant a. Here a is 1.Use that to find the remainder...
    But I don't know what P(x) is so I cannot subsititute a...

    Thnak you for your help
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    (Original post by Cycy12)
    Thank you for your help!

    So, do i just divide 2x+3 by x+1 and look at this remainder?
    Yes - as Pronged Lily said.
 
 
 
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