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    I just have no idea where to start with this question to get a sensible answer...
    I've tried rearranging p=RA/L to find L but it doesn't really work :/
    I'm probably over complicating it but any help would be much appreciated Name:  20151029_194212-1.jpg
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    (Original post by rainbowtwist)
    I just have no idea where to start with this question to get a sensible answer...
    I've tried rearranging p=RA/L to find L but it doesn't really work :/
    I'm probably over complicating it but any help would be much appreciated Name:  20151029_194212-1.jpg
Views: 208
Size:  196.4 KB
    That sounds like a good idea

    What does your calculation look like?
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    Well, it tells you that your length is 'x'. Therefore, your area must be 'x' to the power of 2 ( as x is multiplied by itself).

    So, if you substitute it, the you get p=R(x)2/x

    Cancel your x's to get p=Rx

    Rearrange and you get x=p/R, which is 5x10-2/5 = 0.01m
    Hope this helps

    P.s, if you substitute it into the equation you'll see that the answer for resistivity is 0.05, which is 5x10-2
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    (Original post by JC_Costales)
    Well, it tells you that your length is 'x'. Therefore, your area must be 'x' to the power of 2 ( as x is multiplied by itself).

    So, if you substitute it, the you get p=R(x)2/x

    Cancel your x's to get p=Rx

    Rearrange and you get x=p/R, which is 5x10-2/5 = 0.01m
    Hope this helps

    P.s, if you substitute it into the equation you'll see that the answer for resistivity is 0.05, which is 5x10-2
    Thank you !! Yes I understand - I had the right idea but I think I was getting myself all confused because I rearranged it first and subbed in R straight away :rolleyes:
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    (Original post by rainbowtwist)
    Thank you !! Yes I understand - I had the right idea but I think I was getting myself all confused because I rearranged it first and subbed in R straight away :rolleyes:
    It's Ok!!!! everyone makes little slip ups once in a while, it's what makes us fundamentally human
 
 
 
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