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MEI S2 Poissons Distribution Help me watch

1. Hello there I have got really stuck on the following question can someone show me how to solve it. Thanks.

Fanfold paper for computer printers is made by putting perforations every 30 cm in a continuous roll of paper. A box of fanfold paper contains 2000 sheets.
(i) State the length of the continuous rolls from which the box of paper is produced.

The manufactures claim that faults occur at random and at an average rate of 1 per 240 meters of paper.
(ii) State an appropriated distribution for the number of faults per box of paper. Find the probability that a box op paper has no faults and also that it has more than 4 faults.

2 copies of a report which runs to 100 sheets per copy are printed on this sort of paper.
(iii) Find the probability that there are no faults in either copy of the report and also the probability that just one copy is faulty.

Thanks guys for the help
2. (Original post by lewis1008)
Hello there I have got really stuck on the following question can someone show me how to solve it. Thanks.

Fanfold paper for computer printers is made by putting perforations every 30 cm in a continuous roll of paper. A box of fanfold paper contains 2000 sheets.
(i) State the length of the continuous rolls from which the box of paper is produced.

The manufactures claim that faults occur at random and at an average rate of 1 per 240 meters of paper.
(ii) State an appropriated distribution for the number of faults per box of paper. Find the probability that a box op paper has no faults and also that it has more than 4 faults.

2 copies of a report which runs to 100 sheets per copy are printed on this sort of paper.
(iii) Find the probability that there are no faults in either copy of the report and also the probability that just one copy is faulty.

Thanks guys for the help
Let's get you started:

(i) You know each sheet of paper is 30cm long and that there are 2000 sheets in a box. So the total length of paper per box is X = ?

(ii) You have X metres of paper per box, so the expected number of faults per box is X/240 = m. Use m as the mean in a Poisson distribution. What then is P(0)? P(more than four) = 1 - P(0) - P(1) - P(2) - P(3) - P(4).

(iii) Work out the probability that a single book has no faults and work from there...

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