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maths problem watch

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    Solve the equation 2^1 – x = 4^x???
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    Is it  2^{1-x} = 4^x or  2^1 - x = 4^x ?
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    the first one
    (Original post by Jordan\)
    Is it  2^{1-x} = 4^x or  2^1 - x = 4^x ?
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    (Original post by Tango_16)
    the first one
    Ah ok, here's a hint: If you have an equation where the base of every number is the same, then you can just compare the indices.

    i.e  a^b + a^c = a^d , we can then say that  b+c=d
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    (Original post by Jordan\)
    Ah ok, here's a hint: If you have an equation where the base of every number is the same, then you can just compare the indices.

    i.e  a^b + a^c = a^d , we can then say that  b+c=d
    yeah... that doesnt make much sense to me. sorry
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    (Original post by Tango_16)
    yeah... that doesnt make much sense to me. sorry
    Can you see from the equation  2^{1-x} = 4^x how we can make it so that both terms in the equation have the same base?
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    (Original post by Jordan\)
    Can you see from the equation  2^{1-x} = 4^x how we can make it so that both terms in the equation have the same base?
    ah okay i got it, the answer is 1/3 thanks for your help
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    (Original post by Tango_16)
    ah okay i got it, the answer is 1/3 thanks for your help
    No problem
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    (Original post by Jordan\)
    Ah ok, here's a hint: If you have an equation where the base of every number is the same, then you can just compare the indices.

    i.e  a^b + a^c = a^d , we can then say that  b+c=d
    That is incorrect


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