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    So the question is as follows

    The complex number Z satisfies the equation
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    where lambda is a real number

    show that ((2−3λ)(1+λι))/(1+λ2)=z

    after rearranging the equation I got z=(2-3λ)/(1-λi)

    I dont understand where I have gone wrong, could somebody please help me on this.
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    Your rearrangement is correct. Now you just have to rationalist the denominator to get rid of the i.
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    (Original post by chernid)
    Your rearrangement is correct. Now you just have to rationalist the denominator to get rid of the i.
    ah of course, thanks for that.
 
 
 
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Updated: October 31, 2015
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