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    I have a question about Osborn's rule.

    "Use Osborn's rule to convert the following expression, which is given in hyperbolic terms, into an expression containing corresponding trigonometric terms: 4sinh(x+(pi/6))=5.464102cosh(x)"

    I don't know what I need to do.
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    (Original post by mickturner)
    I have a question about Osborn's rule.

    "Use Osborn's rule to convert the following expression, which is given in hyperbolic terms, into an expression containing corresponding trigonometric terms: 4sinh(x+(pi/6))=5.464102cosh(x)"

    I don't know what I need to do.
    Simple, just use the identity for sinh(a+b) on the LHS and then re-arrange the equation. Whenever you see a sin^2 term it's negative in its hyperbolic equivalent as opposed to positive.

    For example usually (using one of the basic trig identities):

    cos^2\theta + sin^2\theta = 1

    but in hyperbolics it's:

    cosh^2\theta -sinh^2\theta = 1

    I hope that helps
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    (Original post by a10)
    Simple, just use the identity for sinh(a+b) on the LHS and then re-arrange the equation. Whenever you see a sin^2 term it's negative in its hyperbolic equivalent as opposed to positive.

    For example usually (using one of the basic trig identities):

    cos^2\theta + sin^2\theta = 1

    but in hyperbolics it's:

    cosh^2\theta -sinh^2\theta = 1

    I hope that helps

    So would my answer look a bit like this?
    4sin(x-(pi-6))=5.46102cos(-x)
 
 
 
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