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1. At 25*C pKw=14
Calculate the concentration of OH- When the concentration of H+ is 1.0x10-2 Moldm-3
2. (Original post by Needhelpasap)
At 25*C pKw=14
Calculate the concentration of OH- When the concentration of H+ is 1.0x10-2 Moldm-3
Kw = 1*10^-14 mol^2dm^-6

Divide Kw by [H+] to get concentration of [OH-] as Kw = [H+] [OH-]
3. (Original post by TheRoyalLobster)
Kw = 1*10^-14 mol^2dm^-6

Divide Kw by [H+] to get concentration of [OH-] as Kw = [H+] [OH-]
1x10-14 / 1.0x10-2 =. 1x10-12
Have I done it right?
Thank you!!
4. (Original post by Needhelpasap)
1x10-14 / 1.0x10-2 =. 1x10-12
Have I done it right?
Thank you!!
Yes looks right to me and no problem! 😊
5. (Original post by TheRoyalLobster)
Yes looks right to me and no problem! 😊
That's brilliant thank you!!
6. (Original post by TheRoyalLobster)
Yes looks right to me and no problem! 😊

Can you check this for me please

Q= calculate the ration of [H+] and [OH-] when pH is 10.

My answer came out to be

OH- is 1x10-4 moldm3
h+ is 1x10-10

I think my answer are wrong
7. That all seems right to me Just learn Kw=[H+][OH-] and Kw = 1*10^-14 at 25 degrees C /298 K and you can't go wrong
8. (Original post by TheRoyalLobster)
That all seems right to me Just learn Kw=[H+][OH-] and Kw = 1*10^-14 at 25 degrees C /298 K and you can't go wrong
Thank you !!
9. Anytime haha :')

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