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    At 25*C pKw=14
    Calculate the concentration of OH- When the concentration of H+ is 1.0x10-2 Moldm-3
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    (Original post by Needhelpasap)
    At 25*C pKw=14
    Calculate the concentration of OH- When the concentration of H+ is 1.0x10-2 Moldm-3
    Kw = 1*10^-14 mol^2dm^-6

    Divide Kw by [H+] to get concentration of [OH-] as Kw = [H+] [OH-]
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    (Original post by TheRoyalLobster)
    Kw = 1*10^-14 mol^2dm^-6

    Divide Kw by [H+] to get concentration of [OH-] as Kw = [H+] [OH-]
    1x10-14 / 1.0x10-2 =. 1x10-12
    Have I done it right?
    Thank you!!
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    (Original post by Needhelpasap)
    1x10-14 / 1.0x10-2 =. 1x10-12
    Have I done it right?
    Thank you!!
    Yes looks right to me and no problem! 😊
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    (Original post by TheRoyalLobster)
    Yes looks right to me and no problem! 😊
    That's brilliant thank you!!
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    (Original post by TheRoyalLobster)
    Yes looks right to me and no problem! 😊


    Can you check this for me please

    Q= calculate the ration of [H+] and [OH-] when pH is 10.

    My answer came out to be

    OH- is 1x10-4 moldm3
    h+ is 1x10-10


    I think my answer are wrong
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    That all seems right to me Just learn Kw=[H+][OH-] and Kw = 1*10^-14 at 25 degrees C /298 K and you can't go wrong
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    (Original post by TheRoyalLobster)
    That all seems right to me Just learn Kw=[H+][OH-] and Kw = 1*10^-14 at 25 degrees C /298 K and you can't go wrong
    Thank you !!
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    Anytime haha :')
 
 
 
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