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# c3 help!!! watch

1. How would you do this?
2. (Original post by Loola1234)
How would you do this?
both questions?

Do you have the correct answers?
3. 1a) rearrange to get lnx=ln6-ln3, using a log rule this would then be lnx=ln2 so x=2
1b) multiply both sides by e^x and rearrange to get e^2x + 4e^x +3=0 , use quadratic formula to find e^x , once you get 2 solutions "ln both sides" to get x
4. (Original post by Hassan55)
1a) rearrange to get lnx=ln6-ln3, using a log rule this would then be lnx=ln2 so x=2
1b) multiply both sides by e^x and rearrange to get e^2x + 4e^x +3=0 , use quadratic formula to find e^x , once you get 2 solutions "ln both sides" to get x
In fact you can factories part b (e^x -1)(e^x -3)=0 so solutions would be e^x=1 and e^x=3 so x=ln1=0 and x=ln3

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Updated: November 7, 2015
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