Hi I am struggling with a question on simplifying boolean algebra, here is the equation:
A.B.(A+B)
I have got it to this stage: (I'm not sure if this is correct or not)
(A.B).(A+B)
Any help on how to simplify this would be appreciated
Thanks
P.S Also if someone could check this I would appreciate it:
Initial equation: (A+B).(A+NOTB)
Final answer:A
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MatthewP15
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- 01-11-2015 11:16
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- 01-11-2015 11:37
(Original post by MatthewP15)
Hi I am struggling with a question on simplifying boolean algebra, here is the equation:
A.B.(A+B)
I have got it to this stage: (I'm not sure if this is correct or not)
(A.B).(A+B)
Any help on how to simplify this would be appreciated
Thanks
P.S Also if someone could check this I would appreciate it:
Initial equation: (A+B).(A+NOTB)
Final answer:A
I'm actually more familiar with set notation for Boolean Algebra, so I made the conversion to find your answer, even so you have:
Now distributingover
and then considering the parts separately before combining you should get your result.
Just as an fyi, you can use Wolfram to check your results. -
MatthewP15
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- 01-11-2015 12:23
(Original post by joostan)
I agree both with your first step above and your result in the P.S.
I'm actually more familiar with set notation for Boolean Algebra, so I made the conversion to find your answer, even so you have:
Now distributingover
and then considering the parts separately before combining you should get your result.
Just as an fyi, you can use Wolfram to check your results. -
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- 02-11-2015 12:04
Your simplification is wrong, you must have made a mistake somewhere.
Distributing the original equation you should have got,
(A + B)(A + ~B) = A(A + ~B) + B(A + ~B) = AA + A.~B + AB + B.~B
you then have to consider the separate terms and simplify. -
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- 03-11-2015 09:18
(Original post by MatthewP15)
Hi I am struggling with a question on simplifying boolean algebra, here is the equation:
A.B.(A+B)
I have got it to this stage: (I'm not sure if this is correct or not)
(A.B).(A+B)
Any help on how to simplify this would be appreciated
Thanks
P.S Also if someone could check this I would appreciate it:
Initial equation: (A+B).(A+NOTB)
Final answer:A
A | 0 1 0 1 |
B | 0 0 1 1 |
======================
Res| 0 0 0 1 | = A.B
Alas, I have no idea how you would prove that mathematically. I hated this theoretic nonsense at uni. Absolutely no use in the real world sadly.
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