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    how do i differentiate x^7 with respect to x? i've not been taught this and cannot find useful information online.
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    Being the power down and then subtract 1 from the power.

    So 7x^6


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    (Original post by caitlindavies)
    how do i differentiate x^7 with respect to x? i've not been taught this and cannot find useful information online.
    step 1: multiply the X by 7
    answer: 7x^7

    Step 2: minus 1 away from the power

    final answer: 7x^6
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    (Original post by caitlindavies)
    how do i differentiate x^7 with respect to x? i've not been taught this and cannot find useful information online.
    x^n differentiates into nx^(n-1)
    So it would be 7x^6.
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    http://www.dummies.com/how-to/conten...ion-rules.html

    so f(x) = x^7
    f'(x) = 7x^6
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    thanks everyone! as soon as i posted it clicked, what do i do if it says 7x^2?
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    (Original post by york_wbu)
    x^n differentiates into nx^(n-1)
    So it would be 7x^6.
    (Original post by Bloom77)
    step 1: multiply the X by 7
    answer: 7x^7

    Step 2: minus 1 away from the power

    final answer: 7x^6
    (Original post by AmateurMathsGeek)
    Being the power down and then subtract 1 from the power.

    So 7x^6


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    That's incorrect
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    (Original post by AK 12)
    That's incorrect
    sorry, what i mean is what if the question asks x^4 + 7x^2
    would it be 4x^3 + 14x?
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    Differentiating (x)^7 wrtx is solvable using chain rule.

    d/dx[(x)^7] = [7x^6] * 1. You always multiply by the devrivate of the bracket. d/dx[(x^3)^7] = 7x^18*3x^2
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    (Original post by AK 12)
    Differentiating (x)^7 wrtx is solvable using chain rule.

    d/dx[(x)^7] = [7x^6] * 1. You always multiply by the devrivate of the bracket. d/dx[(x^3)^7] = 7x^18*3x^2
    Why are you posting about the chain rule?
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    (Original post by AK 12)
    Differentiating (x)^7 wrtx is solvable using chain rule.

    d/dx[(x)^7] = [7x^6] * 1. You always multiply by the devrivate of the bracket. d/dx[(x^3)^7] = 7x^18*3x^2
    Im dead 😂😂😂


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    (Original post by AK 12)
    Differentiating (x)^7 wrtx is solvable using chain rule.

    d/dx[(x)^7] = [7x^6] * 1. You always multiply by the devrivate of the bracket. d/dx[(x^3)^7] = 7x^18*3x^2
    Please don't troll people who are trying to give constructive suggestions!
 
 
 
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