Hi ! I'm stuck on this exercise.
A solution of 100mL of Hydrogen sulfide H2S is mixed with 10mL of a solution of OH-.
So there are two equilibrium and I need to calculate the pH of the resulting solution.
Could you please give me any hints ? Thank you !
H2S --> c=0.02 M ;
OH --> c=0.1 M ;
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pH of 2 mixed solutions watch
- Thread Starter
- 01-11-2015 11:50
- 01-11-2015 14:32
H2S + OH- <-> HS- + H2O
HS- + OH- <-> S2- + H2O
How many mol of each chemical do you have? Enough to push the first equilibrium to the right? Enough to push the second one?