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    8x-1 ... how do i differentiate with respect to x?
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    write as 8x1 -1x0

    then apply the rules for differentiating axn
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    (Original post by caitlindavies)
    8x-1 ... how do i differentiate with respect to x?
    Differentiate each term with respect to x.

    How do you differentiate the general term ax^n, where a and n are numbers, with respect to x?
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    (Original post by caitlindavies)
    8x-1 ... how do i differentiate with respect to x?
    Times by the power and then take one away from the power.
    For example 16x^2 would be 32x. You're timesing by the power (2) and then taking one away from the power (2-1).

    Hope that makes it clearer as to how to do your question.

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    (Original post by caitlindavies)
    8x-1 ... how do i differentiate with respect to x?
    Is that 8/x ?

    Use the rule for ax^n ... d/dx =
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    d/dx[axn] = naxn-1
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    (Original post by ultimatesword)
    Times by the power and then take one away from the power.
    For example 16x^2 would be 32x. You're timesing by the power (2) and then taking one away from the power (2-1).

    Hope that makes it clearer as to how to do your question.

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    but there is no power?
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    (Original post by caitlindavies)
    but there is no power?
    There is, it's just 1 and 0.

    1 is 1x^0. remember that power of 0 makes 1.
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    for example, y = 10x + 2
    if you differentiate y with respect to x, you'd get dy/dx = 10
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    (Original post by Raees_Sharif)
    for example, y = 10x + 2
    if you differentiate y with respect to x, you'd get dy/dx = 10
    so does the answer to 8x-1 dy/dx + 8?
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    (Original post by caitlindavies)
    so does the answer to 8x-1 dy/dx + 8?
    if you meant '=' when you said '+' you are correct.
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    (Original post by Raees_Sharif)
    if you meant '=' when you said '+' you are correct.
    yeah i did woah thank you that makes sense now!!
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    (Original post by caitlindavies)
    but there is no power?
    everything has a power, but people don't usually write the power if the value is to the power of 1.
 
 
 
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