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1. A cricket bat causes an acceleration of 3400 m s–2 to a cricket ball travelling horizontally at 30 m s–1. After contact with the bat, the ball is travelling at 25 m s–1 in the opposite direction to its original motion.
i Calculate the time that the ball was in contact with the bat.

time = ms (2 marks)
ii Describe how you would determine, experimentally, the speed of the cricket ball as it left the bat.
2. (Original post by lovelyqueen)
A cricket bat causes an acceleration of 3400 m s–2 to a cricket ball travelling horizontally at 30 m s–1. After contact with the bat, the ball is travelling at 25 m s–1 in the opposite direction to its original motion.
i Calculate the time that the ball was in contact with the bat.

time = ms (2 marks)
ii Describe how you would determine, experimentally, the speed of the cricket ball as it left the bat.
For the first part, you know that a=(change in velocity)/(change in time). Note that you need to take account of the direction of the velocity before and after.

For the second part, it would be better to look at the suvat equations and pick the one whose variables can be put into experiment to find the initial velocity of the ball and, then choose an experiment accordingly. I think for simplicity you could use two suvat equations without having to measure any time taken.

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Updated: November 1, 2015
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