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# Help on c1 questions watch

2. Which exam board is this???
3. (Original post by SeanFM)
6 mainly and I've done non I don't get it lol

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4. (Original post by SargentZenj2)
Which exam board is this???
Aqa how come

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5. [QUOTE=lkjhgfdsasd;60325977]Aqa how come

Edexcel. Its because the C1 for you is C2 for us and we dont do circle equations and such this c2
6. [QUOTE=lkjhgfdsasd;60325949]6 mainly and I've done non I don't get it lol

for 6ai
Let F(x) = x^3 + x^2 -10x +8
So F(2) = 2^3 + 2^2 -(10x2) +8 =
Therefore X-2 is a factor of X^3 + x^2 -10x +8

For 6aii
Use long division and youll find
X^3 +X^2 -10X + 8 = (X-2)(X^2+3X-4)

Then factorise X^2 +3x - 4 = (X-1)(X+4)
so therfore
X^3 +X^2 -10X + 8= (x-2)(x-1)(x+4) <= those are the factors.

For 6b a>0 so its a normal cubic curve
the x intercepts when y=0 are (2,0)(1,0)(-4,0)
When x=0 the y intercept is (0,8)
Since this is a sketch just plot these points only, you dont need to work out anything else. It should be a rough drawing
. Sorry this took so long
7. [QUOTE=SargentZenj2;60326277]
(Original post by lkjhgfdsasd)
6 mainly and I've done non I don't get it lol

for 6ai
Let F(x) = x^3 + x^2 -10x +8
So F(2) = 2^3 + 2^2 -(10x2) +8 =
Therefore X-2 is a factor of X^3 + x^2 -10x +8

For 6aii
Use long division and youll find
X^3 +X^2 -10X + 8 = (X-2)(X^2+3X-4)

Then factorise X^2 +3x - 4 = (X-1)(X+4)
so therfore
X^3 +X^2 -10X + 8= (x-2)(x-1)(x+4) <= those are the factors.

For 6b a>0 so its a normal cubic curve
the x intercepts when y=0 are (2,0)(1,0)(-4,0)
When x=0 the y intercept is (0,8)
Since this is a sketch just plot these points only, you dont need to work out anything else. It should be a rough drawing
. Sorry this took so long
Thanksss I'm going to check this out properly in a bit after I've done the first two questions and you were fast tho

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8. [QUOTE=SargentZenj2;60326061]
(Original post by lkjhgfdsasd)
Aqa how come

Edexcel. Its because the C1 for you is C2 for us and we dont do circle equations and such this c2
Ohh right

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