The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

Edexcel FP2 Official 2016 Exam Thread - 8th June 2016

Scroll to see replies

Original post by Ewanclementson
Answers - let me know if they need to be edited (edit - typo on 5 and 3 fixed)
1) -2<x<-root2 -1<x<root2
2) shown x(x^2-3x-9)/2(x+2)
3)e^ipi(1/24, 13/24, -11/24, -23/24) shown
4) r/q(1-e^-(q/p)t) (2sinx-cosx+e^-2)/5
5) Coefficients are 1/16, -5/16, 10/16 shown
6) coefficients are 1 2 2 8/3 then shown
7) Ax^2+Bx-1/12x^(-2)
8) 21/4, (+-)arcos(3/4) 32.519 which I think was 3root7/4-11arcos3/4+49pi/4
Hope this helps everyone


I got exactly the same

Posted from TSR Mobile
Original post by smartalan73
yeah that's still different to what I got so would still like to know how you did it? I'm awful at complex numbers.


Oh I did it in the principle argument range -pi<=x<=pi but you could do it in the 0<=x<=2pi range as well and get different values.
Original post by Louisb19
STEPers across England smiled when they saw ∫e2θsin⁡θdθ \displaystyle\int e^{2 \theta} \sin{\theta} \mathrm{d} \theta .


I recognised it from my procatination on such threads. I too smiled.
Original post by ninjass
Is it just me - or was 4c a lot easier than first glace - I got it but in a really complicated way

I think i got 70/75 - UMS predictions??


Probably a B or C
Original post by sweeneyrod
In C3/C4? I don't think our class learnt it in any case.


Surely your class learnt how to re-arrange equations of the form a = b + ka?
Original post by Zacken
It's in your formula booklet.


Where abouts? I only saw The sum for r^2 and r^3.
Original post by daniella_n
I meant I messed up so bad in that question that I didn't even have e2x sinx anywhere :smile: :smile: fun times


Posted from TSR Mobile

Ah I see that's unfortunate I guess we got to hope for low grade boundaries.
Original post by Mathemagicien
I did question 4 directly, not by parts, using exponential version of sin x.


But its sinx not sinh x
Original post by Mattematics
Where abouts? I only saw The sum for r^2 and r^3.


Arithmetic series. C1 section. S_n = n/2(1 + n).
Original post by Mattematics
Where abouts? I only saw The sum for r^2 and r^3.


I don't think it's in there. I had a quick glance before reaching into the depths of my mind to retrieve it.

EDIT: Never mind, Zacken's right haha
Original post by Mattematics
Where abouts? I only saw The sum for r^2 and r^3.


arithmetic series:

sn = n/2 (a + l)

here a = 1, l = n
Predict the grade boundaries:
http://www.thestudentroom.co.uk/showthread.php?t=4149979
Original post by anhaanha
But its sinx not sinh x


So? sin x also has a exponential definition, you have heard of DeMoivre's, surely...?

Original post by cjlh
I don't think it's in there. I had a quick glance before reaching into the depths of my mind to retrieve it.


Arithmetic series. C1 (!) section.
Original post by Zacken
Arithmetic series. C1 section. S_n = n/2(1 + n).


you f***ing ninja
Original post by Zacken
Surely your class learnt how to re-arrange equations of the form a = b + ka?


I think it's a bit of a stretch to say it's on the syllabus. There aren't any examples of IBP being used that way in the text book so it's a bit of a sneaky question. Yes if you think about it it makes sense but if you've never seen anything of that type then it's not exactly a c4 integral
Original post by cjlh
I might have gotten the same though, -11. Is that definitely wrong? I remember changing a sign on a +6n after going back. If that's wrong I'm a *******.


I am quite sure what I put was correct (-9) as I used the sum function on my calculator to check it for n=1,2 and 3 and it worked for all of them; this would not have been so for a different value in place of the -9.
Original post by Student403
Nope the coefficients of sinx and cosx didnt have e-2theta in the final answer


yeah because e^2x y = 1/5e^2x * (2sinx - cosx) + c

therefore

y = 1/5 (2sinx - cosx) + ce^2x
[QUOTE=AlexFrangos;65555783]What did you get in question 2 and in 2nd order differential equation?

Cant recall wts Q2, inequality?

-1-rt11 <x< -2 , -1+rt11 <x< 4, 4 critical values

2nd order: -5e^-x + fraction (3/4?i forgot)e^-2x + sth + sth + 17/4 😂 sorry i cant recall the answer
Original post by RThornton
yeah because e^2x y = 1/5e^2x * (2sinx - cosx) + c

therefore

y = 1/5 (2sinx - cosx) + ce^2x


Correct except it's ce^-2x
Original post by Ewanclementson
Answers - let me know if they need to be edited
1) -2<x<-root2 -1<x<root2
2) shown x(x^2-3x-9)/2(x+2)
3)e^ipi(1/24, 13/14, -11/24, -23/24) shown
4) r/q(1-e^-(q/p)t) (2sinx-cosx+e^-2)/5
5) Coefficients are 1/16, -5/15, 10/16 shown
6) coefficients are 1 2 2 8/3 then shown
7) Ax^2+Bx-1/12x^(-2)
8) 21/4, (+-)arcos(3/4) 32.519 which I think was 3root7/4-11arcos3/4+49pi/4
Hope this helps everyone!


For question 5 shouldn't the second coefficient be -5/16 because it was -10/32

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you