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    I have a balanced equation for phosphuric acid and sodium carbonate, do the ionic equations include the number of molecules that there are and the amount of atoms within the molecule
    2H3PO4(aq)+3Na2CO3(s)->2Na3PO4(aq)+3CO2(g)+3H2O(l)
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    (Original post by LAnnD)
    I have a balanced equation for phosphuric acid and sodium carbonate, do the ionic equations include the number of molecules that there are and the amount of atoms within the molecule
    2H3PO4(aq)+2Na2CO3(s)->2Na3PO4(aq)+3CO2(g)+3H2O(l)
    Yes, to write an ionic equation, leave out 'spectator ions', which are ions which are the same at the end of the reaction as they were at the beginning. It's easier to do this if you split up any aqueous ionic molecules in that equation into their constituent ions and then write the correct oxidation numbers underneath every molecule. This way it's easy to see which ions have changed, and which haven't.
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    2H3PO4 (aq)+ 2Na2CO3(s) =2Na3PO4(aq) + 3CO2 (g)+ 3H20(L)
    6H+ (aq)+ 2PO43-(aq) + 2Na2CO3 (S) = 2Na+(aq) + 2PO43-(aq) + 3CO2(g)+3H2O(L)
    cross out any spectator ions ( ions that remain the same (are unchanged in this case the spectator ion is 2PO43-)

    Final ionic equation:
    6H+(aq)+2Na2CO3(s)=2Na+(aq)+3CO2 (g)+3H20(l)


    (not sure if this is correct)
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    (Original post by mishmoshmogo)
    2H3PO4 (aq)+ 2Na2CO3(s) =2Na3PO4(aq) + 3CO2 (g)+ 3H20(L)
    6H+ (aq)+ 2PO43-(aq) + 2Na2CO3 (S) = 2Na+(aq) + 2PO43-(aq) + 3CO2(g)+3H2O(L)
    cross out any spectator ions ( ions that remain the same (are unchanged in this case the spectator ion is 2PO43-)

    Final ionic equation:
    6H+(aq)+2Na2CO3(s)=2Na+(aq)+3CO2 (g)+3H20(l)


    (not sure if this is correct)
    Thankyou 😊😃😊
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    (Original post by pineneedles)
    Yes, to write an ionic equation, leave out 'spectator ions', which are ions which are the same at the end of the reaction as they were at the beginning. It's easier to do this if you split up any aqueous ionic molecules in that equation into their constituent ions and then write the correct oxidation numbers underneath every molecule. This way it's easy to see which ions have changed, and which haven't.
    thank you😃😆
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    (Original post by LAnnD)
    I have a balanced equation for phosphuric acid and sodium carbonate, do the ionic equations include the number of molecules that there are and the amount of atoms within the molecule
    2H3PO4(aq)+2Na2CO3(s)->2Na3PO4(aq)+3CO2(g)+3H2O(l)
    This isn't a balanced equation? The sodium (Na) isn't balanced.

    Note: I haven't checked the other atoms, that just stood out to me.

    One can't correctly work out the ionic equation if they don't have the balanced chemical equation.
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    (Original post by Kozmo)
    This isn't a balanced equation? The sodium (Na) isn't balanced.

    Note: I haven't checked the other atoms, that just stood out to me.

    One can't correctly work out the ionic equation if they don't have the balanced chemical equation.
    thank you for pointing this out, it is just a typing error I have it wrote correctly in my notes
 
 
 

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