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    Please !!! 4^3−4(√3+1) ^2+(9+4√3 )x−9=0
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    (Original post by Mathious)
    Please !!! 4^3−4(√3+1) ^2+(9+4√3 )x−9=0
    You need some latex.
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    (Original post by ombtom)
    You need some latex.
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    (Original post by Student403)
    [big ol' picture]
    Exactly.
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    (Original post by ombtom)
    Exactly.
    Protip: Don't google just "latex" in the family living room
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    (Original post by Student403)
    Protip: Don't google just "latex" in the family living room
    That is a good protip. Mathious you should definitely take note of this protip.
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    (Original post by Mathious)
    Please !!! 4^3−4(√3+1) ^2+(9+4√3 )x−9=0
    please post a photo of the question as I am very keen to see it
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    (Original post by Mathious)
    Please !!! 4^3−4(√3+1) ^2+(9+4√3 )x−9=0
     4^3 - 4(\sqrt3 + 1)^2 + (9 + 4\sqrt3)x - 9 = 0

    What part are you struggling with?
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    (Original post by TeeEm)
    please post a photo of the question as I am very keen to see it
    i can't and now ?
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    (Original post by Mathious)
    i can't and now ?
    is it 4x3 or 43 ?
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    (Original post by TeeEm)
    is it 4x3 or 43 ?
    4x3 yes sorry:
    4x3 −4(√3+1)x²+(9+4√3 )x−9=0
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    (Original post by Mathious)
    4x3 yes sorry:
    4x3 −4(√3+1)x²+(9+4√3 )x−9=0
    what level are you on?
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    (Original post by TeeEm)
    what level are you on?
    A-level
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    (Original post by Mathious)
    A-level
    then by inspection


    you hope that there is a rational factor
    look for the divisors of 9 (1,3,9)
    evidently 1 is a zero of the cubic
    divide the linear factor out
    check the discriminant next before you waste time looking for non existent real solutions.

    if there are more solutions, factorize or quadratic formula
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    (Original post by Mathious)
    4x3 yes sorry:
    4x3 −4(√3+1)x²+(9+4√3 )x−9=0

    (Original post by Mathious)
    A-level
    Is that the entire, original question? I'd be very surprised if you were just given that as an A level question
 
 
 
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