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    How do you factorise?
    y=6x^2 - 13x - 8
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    (Original post by Custardcream000)
    How do you factorise?
    y=6x^2 - 13x - 8
    How you would usually factorise it, but a bit tricker as there is an 'a' term.
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    If an equation is of the form ax^2 + bx + c, then you want two numbers that multiply to give (a*c) (in this case 6*-8) and add to give b (in this case -13) if that rings any bells.
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    (Original post by Custardcream000)
    How do you factorise?
    y=6x^2 - 13x - 8
    Think of two numbers that multiply to give -48 and add to give -13 and SeanFM said above. Then try to re-write the equation using those new two numbers so 6x^2 ... .... - 8 = 0
    Then, we'll guide you next unless you know what to do .

    Please, don't forget to post your working out!
 
 
 
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