How to Combine Bijections to get all real integers to A or B
if f: Z+ > A and g: Z+ > B
how do you show that you can combine them to get h: Z+ > AUB?
Given that f and g are bijections?
Very stuck :/
how do you show that you can combine them to get h: Z+ > AUB?
Given that f and g are bijections?
Very stuck :/
Original post by around
Hint: can you find two copies of Z+ inside Z+?
Two copies?
Original post by EllieLC
Two copies?
Well, if you could find two copies of Z+ inside Z+, you could map one to A using f, and one to B using g.
So Z+ = {0, 1, 2, 3, ...}. Can you divide this set into two?
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