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Coordinate Geometry C4 HELP! watch

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    How can I solve this???

    Many thanks in advance.
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    (Original post by Scopeowner)
    How can I solve this???

    Thanks in advance
    I think you forgot to upload a photo, I'd be happy to help though!
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    Name:  CG4.JPG
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    Sorry, my computer has been messing me around. Please find attached the photo...
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    (Original post by Scopeowner)
    Name:  CG4.JPG
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    Sorry, my computer has been messing me around. Please find attached the photo...
    Given that this curve crosses the x-axis at a point X, we may deduce that when
    y = 0, x = X \implies (X,0)

    likewise:
    x = 0, y = Y \implies (0,Y)

    Then you want to find the values of the variable t for y = 0 and x = 0 respectively

    If the t^3 + 1 = 0 is the part that is confusing you, let f(x) = t^3 + 1 and notice that f(-1) = (-1)^3 + 1 = 0 does this give you a clue how to factorise this expression?
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    (Original post by JakeThomasLee)
    Given that this curve crosses the x-axis at a point X, we may deduce that when
    y = 0, x = X \implies (X,0)

    likewise:
    x = 0, y = Y \implies (0,Y)

    Then you want to find the values of the variable t for y = 0 and x = 0 respectively

    If the t^3 + 1 = 0 is the part that is confusing you, let f(x) = t^3 + 1 and notice that f(-1) = (-1)^3 + 1 = 0 does this give you a clue how to factorise this expression?
    Hmm, I am still stuck. After working out the value of 't' when y = 0, I can't seem to work out the value of 'q' for which I keep on getting as 0. Any chance of you showing me some working? Because I've been stuck on this question for ages now.
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    (Original post by Scopeowner)
    Hmm, I am still stuck. After working out the value of 't' when y = 0, I can't seem to work out the value of 'q' for which I keep on getting as 0. Any chance of you showing me some working? Because I've been stuck on this question for ages now.
    Name:  Coordinate Geom Q1.jpeg
Views: 41
Size:  153.1 KB

    Do let me know if the answer is different or if I made a mistake though! (It's been a long day)
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    (Original post by JakeThomasLee)
    Name:  Coordinate Geom Q1.jpeg
Views: 41
Size:  153.1 KB

    Do let me know if the answer is different or if I made a mistake though! (It's been a long day)
    No, there has been no mistake. Thank you very much for your all of your help, it makes a lot more sense now.

    I have managed to attempt the question and I got the exact same answer as you which is '8/3'. I have verified this with the answer book and it is correct!

    Once again, thank you so much for your kind help!
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    (Original post by Scopeowner)
    No, there has been no mistake. Thank you very much for your all of your help, it makes a lot more sense now.

    I have managed to attempt the question and I got the exact same answer as you which is '8/3'. I have verified this with the answer book and it is correct!

    Once again, thank you so much for your kind help!
    My pleasure

    Have fun!
 
 
 
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