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Trigonometry watch

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    Hi, I know when doing trigonometry that if the if a side is at the bottom of ten equation so AB\8 =sin 60 that you would times the 8 by sin 60 but what would you do if the unknown is at the bottom? Sorry if it's too vague
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    Do you have a picture of the question?
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    (Original post by Foreverton)
    Do you have a picture of the question?
    No sorry😁
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    (Original post by Holidaylover647)
    No sorry😁
    I don't really understand the question
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    Do you mean when you're looking for an unknown side and you have one side and one angle?
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    (Original post by Foreverton;[url="tel:60403481")
    60403481[/url]]Do you mean when you're looking for an unknown side and you have one side and one angle?
    It's fine, I've finally found something on it! Thanks anyway☺️
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    (Original post by Holidaylover647)
    It's fine, I've finally found something on it! Thanks anyway☺️
    Alright then
    Feel free to ask about any other maths questions though!
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    (Original post by Foreverton)
    Alright then
    Feel free to ask about any other maths questions though!

    Hey is it possible for you to help me with this question?

    (b) By writing the following equation as quadratics in tan θ/2, solve, in the
    interval 0 ≤ θ ≤ 360°:

    (i) sinθ + 2cosθ = 1
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    (Original post by Lilly1234567890)
    Hey is it possible for you to help me with this question?

    (b) By writing the following equation as quadratics in tan θ/2, solve, in the
    interval 0 ≤ θ ≤ 360°:

    (i) sinθ + 2cosθ = 1
    I have no idea sorry 😁
    I'm only year 10

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    (Original post by Foreverton)
    I have no idea sorry 😁
    I'm only year 10

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    OH sozzzz
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    (Original post by Lilly1234567890)
    OH sozzzz
    What year are you?


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    (Original post by Lilly1234567890)
    Hey is it possible for you to help me with this question?

    (b) By writing the following equation as quadratics in tan θ/2, solve, in the
    interval 0 ≤ θ ≤ 360°:

    (i) sinθ + 2cosθ = 1
    Well you would first work out what θ equals by using the trigonometric equations, then you would substitute θ into tan θ/2 to get the angle. I assume that is what you would do anyways, been a while since I've done trig.
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    Well when i checked on solutionbank,
    the first step was to:
    Let tan θ/2=t

    Then it changed to:
    2t/1+t^2 + 2(1-t^2)/1+t^2 = 1

    I just dont get that
 
 
 
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