Below is a picture. I want to know how you can prove that x or Angle CAB is equal to y-180 or angle CDB
x
Turn on thread page Beta
-
Himtiaz
- Follow
- 7 followers
- 12 badges
- Send a private message to Himtiaz
- Thread Starter
Offline12ReputationRep:- Follow
- 1
- 05-11-2015 17:31
-
Himtiaz
- Follow
- 7 followers
- 12 badges
- Send a private message to Himtiaz
- Thread Starter
Offline12ReputationRep:- Follow
- 2
- 05-11-2015 17:34
There is the picture. HELP! P.S: Clicking on it makes it bigger.
-
justinawe
- Follow
- 14 followers
- 18 badges
- Send a private message to justinawe
Offline18ReputationRep:- Follow
- 3
- 05-11-2015 17:54
Just to be sure, was it stated that CD is a tangent to the circle?
-
Himtiaz
- Follow
- 7 followers
- 12 badges
- Send a private message to Himtiaz
- Thread Starter
Offline12ReputationRep:- Follow
- 4
- 05-11-2015 18:08
(Original post by justinawe)
Just to be sure, was it stated that CD is a tangent to the circle? -
justinawe
- Follow
- 14 followers
- 18 badges
- Send a private message to justinawe
Offline18ReputationRep:- Follow
- 5
- 05-11-2015 18:17
Ok then, these are the things you should note:
Angle CDB is 180-y degrees. as triangle BCD is an isosceles triangle, angle BCD will be the same.
given that CD is a tangent to the circle, then what is angle ACD? using this and 180-y for angle BCD, you can find angle ACB.
as triangle ABC is in a semi-circle, what does this make angle ABC?
With this info you should be able to show that x = 180-y -
Himtiaz
- Follow
- 7 followers
- 12 badges
- Send a private message to Himtiaz
- Thread Starter
Offline12ReputationRep:- Follow
- 6
- 05-11-2015 20:29
I still can't work it out
-
Himtiaz
- Follow
- 7 followers
- 12 badges
- Send a private message to Himtiaz
- Thread Starter
Offline12ReputationRep:- Follow
- 7
- 05-11-2015 20:30
(Original post by justinawe)
Ok then, these are the things you should note:
Angle CDB is 180-y degrees. as triangle BCD is an isosceles triangle, angle BCD will be the same.
given that CD is a tangent to the circle, then what is angle ACD? using this and 180-y for angle BCD, you can find angle ACB.
as triangle ABC is in a semi-circle, what does this make angle ABC?
With this info you should be able to show that x = 180-y -
Himtiaz
- Follow
- 7 followers
- 12 badges
- Send a private message to Himtiaz
- Thread Starter
Offline12ReputationRep:- Follow
- 8
- 05-11-2015 21:32
(Original post by justinawe)
Ok then, these are the things you should note:
Angle CDB is 180-y degrees. as triangle BCD is an isosceles triangle, angle BCD will be the same.
given that CD is a tangent to the circle, then what is angle ACD? using this and 180-y for angle BCD, you can find angle ACB.
as triangle ABC is in a semi-circle, what does this make angle ABC?
With this info you should be able to show that x = 180-y -
- Follow
- 9
- 05-11-2015 22:25
Use the alternate segment theorem: the angle between a tangent and a chord at the point of contact is equal to the angle subtended by the chord.
-
Himtiaz
- Follow
- 7 followers
- 12 badges
- Send a private message to Himtiaz
- Thread Starter
Offline12ReputationRep:- Follow
- 10
- 05-11-2015 23:03
Thanks
Reply
Submit reply
Turn on thread page Beta
Related discussions:
TSR Support Team
We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.
This forum is supported by:
- Gingerbread101
- RDKGames
- Changing Skies
- F1's Finest
- rayquaza17
- SherlockHolmes
- davros
- charco
- Kvothe the Arcane
- TeeEff
- The Empire Odyssey
- Protostar
- TheConfusedMedic
- Notnek
- Mr M
- nisha.sri
- claireestelle
- Doonesbury
- furryface12
- Amefish
- harryleavey
- Lemur14
- brainzistheword
- Rexar
- Sonechka
- TheAnxiousSloth
- EstelOfTheEyrie
- CoffeeAndPolitics
- an_atheist
- Labrador99
- EmilySarah00
Updated: November 5, 2015
Share this discussion:
Tweet