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    How do you work out the concentration of H+ ions of a diprotic acid.

    For example (this is the question but made up numbers).

    H2SO4 has a pH 2.50

    Work out the concetation of H+ / [H+].

    How do you do this since its diprotic?

    I know the first step (I think) is to do 10 to the power -2.50.

    Then what? Divide by 2???
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    (Original post by Slenderman)
    How do you work out the concentration of H+ ions of a diprotic acid.

    For example (this is the question but made up numbers).

    H2SO4 has a pH 2.50

    Work out the concetation of H+ / [H+].

    How do you do this since its diprotic?

    I know the first step (I think) is to do 10 to the power -2.50.

    Then what? Divide by 2???
    You don't actually have to assume that the acid is 100% dissociated to answer the question.

    Remember that the pH = -log[H+]

    and you are simply asked for [H+]
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    Yes but surely if it's diprotic, it requires it be divided by two???
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    (Original post by Slenderman)
    Yes but surely if it's diprotic, it requires it be divided by two???
    you are not asked for the concentration of sulphuric acid!!
 
 
 
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